What is "if siobhan hits a 0.25 kg volleyball with 0.5 n of force?

If Siobhan hits a 0.25 kg volleyball with a force of 0.5 N, we can calculate the acceleration of the volleyball using Newton's second law of motion:

F = ma

Here, F is the force applied by Siobhan, m is the mass of the volleyball, and a is the acceleration of the volleyball.

So, rearranging the formula we get:

a = F/m

Substituting the values, we get:

a = 0.5 N / 0.25 kg a = 2 m/s^2

Therefore, the acceleration of the volleyball when Siobhan hits it with a force of 0.5 N is 2 m/s^2. This means that the volleyball will accelerate at a rate of 2 meters per second squared in the direction of the force applied by Siobhan.